Integration Introduction

Introduction (High School Level)

Indefinite and Definite Integrals

Overview

Relationship between Differentiation and Integration A concept diagram showing that integrating f(x) gives F(x), differentiating F(x) returns f(x), and the correspondence between the definite integral and area. Integration Differentiation Definite integral = Area Fundamental Theorem of Calculus $f(x)$ $F(x)$ $a$ $b$ $\displaystyle\int_a^b f(x)\,dx = F(b) - F(a)$

In this introduction, we cover the fundamentals of integration as taught in high school mathematics. You will learn about the indefinite integral as the reverse operation of differentiation, the definite integral for computing areas, and the techniques of integration by substitution and integration by parts.

Learning Goals

  • Understand the concept and basic formulas of indefinite integrals
  • Understand the relationship between definite integrals and area
  • Master integration by substitution and integration by parts
  • Understand applications of integration (area and volume)

Table of Contents

Chapter 1 Indefinite Integral

Antiderivatives, constant of integration, basic formulas

Proofs
Chapter 2 Definite Integral

Definition of the definite integral, area, fundamental theorem

Proofs
Chapter 3 Integration by Substitution

Substitution method, trigonometric substitution

Proofs
Chapter 4 Integration by Parts

Integration by parts, worked examples

Proofs
Chapter 5 Area Calculation

Area enclosed by curves, area between two curves

Proofs
Chapter 6 Volume Calculation

Volume of solids of revolution, volume by cross-sectional area

Proofs

Prerequisites

  • Basics of differentiation (computing derivatives)
  • Basics of trigonometric, exponential, and logarithmic functions

Basic Formulas

Basic Indefinite Integrals

$$\int x^n \, dx = \frac{x^{n+1}}{n+1} + C \quad (n \neq -1)$$ $$\int \frac{1}{x} \, dx = \ln|x| + C$$ $$\int e^x \, dx = e^x + C$$ $$\int \sin x \, dx = -\cos x + C$$ $$\int \cos x \, dx = \sin x + C$$

Fundamental Theorem of Calculus

When $F'(x) = f(x)$:

$$\int_a^b f(x) \, dx = F(b) - F(a) = [F(x)]_a^b$$

Integration by Parts

$$\int f(x)g'(x) \, dx = f(x)g(x) - \int f'(x)g(x) \, dx$$