Definition of the Fourier Transform
From Periodic to Non-Periodic Functions
Intermediate (undergraduate, years 2–3)
Introduction
The Fourier series is a tool for periodic functions, yet in practice many signals are non-periodic. The Fourier transform extends the Fourier series to non-periodic functions, yielding a continuous frequency spectrum.
Derivation from the Fourier Series
The complex Fourier series of a function of period $2L$:
$$f(x) = \displaystyle\sum_{n=-\infty}^{\infty}c_n e^{in\pi x/L}, \quad c_n = \dfrac{1}{2L}\displaystyle\int_{-L}^{L}f(x)e^{-in\pi x/L}\,dx$$
Setting $\omega_n = \dfrac{n\pi}{L}$ (the discrete frequencies) and $\Delta\omega = \dfrac{\pi}{L}$:
$$f(x) = \displaystyle\sum_{n=-\infty}^{\infty}\dfrac{\Delta\omega}{2\pi}\left[\displaystyle\int_{-L}^{L}f(t)e^{-i\omega_n t}\,dt\right]e^{i\omega_n x}$$
As $L \to \infty$, we have $\Delta\omega \to d\omega$ and the sum passes into an integral:
$$f(x) = \dfrac{1}{2\pi}\displaystyle\int_{-\infty}^{\infty}\left[\displaystyle\int_{-\infty}^{\infty}f(t)e^{-i\omega t}\,dt\right]e^{i\omega x}\,d\omega$$
Definition of the Fourier Transform
Fourier transform
$$\hat{f}(\omega) = \mathcal{F}[f](\omega) = \displaystyle\int_{-\infty}^{\infty}f(x)e^{-i\omega x}\,dx$$
Inverse Fourier transform
$$f(x) = \mathcal{F}^{-1}[\hat{f}](x) = \dfrac{1}{2\pi}\displaystyle\int_{-\infty}^{\infty}\hat{f}(\omega)e^{i\omega x}\,d\omega$$
On Notation
- $\hat{f}(\omega)$ or $F(\omega)$: the Fourier transform of $f(x)$
- $\omega$: the angular frequency ($\omega = 2\pi\nu$, where $\nu$ is the ordinary frequency)
Choice of constants
The placement of constants varies between sources. Commonly used conventions are:
- Physics: the convention used here ($1$ and $\dfrac{1}{2\pi}$)
- Engineering: $\dfrac{1}{\sqrt{2\pi}}$ and $\dfrac{1}{\sqrt{2\pi}}$ (symmetric)
- Using the frequency $\nu$: $\displaystyle\int f(t)e^{-2\pi i\nu t}\,dt$ and $\displaystyle\int \hat{f}(\nu)e^{2\pi i\nu t}\,d\nu$
Existence Conditions
Sufficient conditions for the Fourier transform to exist:
Absolute integrability
$$\displaystyle\int_{-\infty}^{\infty}|f(x)|\,dx < \infty$$
A function satisfying this condition is said to belong to $L^1(\mathbb{R})$.
Square integrability
$$\displaystyle\int_{-\infty}^{\infty}|f(x)|^2\,dx < \infty$$
A function satisfying this condition is said to belong to $L^2(\mathbb{R})$. By Plancherel's theorem, the Fourier transform of an $L^2$ function is also well defined.
Continuous Spectrum
For the Fourier series, amplitudes are given at the discrete frequencies $\omega_n = \dfrac{n\pi}{L}$. For the Fourier transform, a spectrum is defined for every continuous frequency $\omega$.
Power spectrum
$$S(\omega) = |\hat{f}(\omega)|^2$$
This represents the energy density of each frequency component.
Phase spectrum
$$\phi(\omega) = \arg(\hat{f}(\omega))$$
This represents the phase of each frequency component.
Worked Examples
Example 1: One-sided exponential decay
$$f(x) = \begin{cases} e^{-ax} & (x \geq 0, a > 0) \\ 0 & (x < 0) \end{cases}$$
$$\hat{f}(\omega) = \displaystyle\int_0^{\infty}e^{-ax}e^{-i\omega x}\,dx = \displaystyle\int_0^{\infty}e^{-(a+i\omega)x}\,dx = \dfrac{1}{a + i\omega}$$
Example 2: Two-sided exponential decay
$$f(x) = e^{-a|x|} \quad (a > 0)$$
$$\hat{f}(\omega) = \displaystyle\int_{-\infty}^{\infty}e^{-a|x|}e^{-i\omega x}\,dx = \displaystyle\int_{-\infty}^{0}e^{ax}e^{-i\omega x}\,dx + \displaystyle\int_0^{\infty}e^{-ax}e^{-i\omega x}\,dx$$
$$= \dfrac{1}{a - i\omega} + \dfrac{1}{a + i\omega} = \dfrac{2a}{a^2 + \omega^2}$$
Conditions for Inversion
For the inverse Fourier transform to recover the original function:
- At a point where $f(x)$ is continuous, it recovers $f(x)$.
- At a discontinuity, it recovers $\dfrac{f(x^+) + f(x^-)}{2}$.
This is the transform analogue of the convergence theorems for the Fourier series.
Summary
- Fourier transform: $\hat{f}(\omega) = \displaystyle\int_{-\infty}^{\infty}f(x)e^{-i\omega x}\,dx$
- Inverse Fourier transform: $f(x) = \dfrac{1}{2\pi}\displaystyle\int_{-\infty}^{\infty}\hat{f}(\omega)e^{i\omega x}\,d\omega$
- It gives a continuous spectrum for non-periodic functions.
- It applies to absolutely integrable or square-integrable functions.
Frequently Asked Questions
Q1: What is the Fourier transform?
A: The Fourier transform maps a function $f(t)$ into the frequency domain $F(\omega)$ and is defined by $F(\omega) = \int_{-\infty}^{\infty} f(t)e^{-i\omega t}\,dt$. It reveals which frequency components a signal contains and with what strength.
Q2: What is the inverse Fourier transform?
A: The inverse Fourier transform is defined by $f(t) = \dfrac{1}{2\pi}\int_{-\infty}^{\infty} F(\omega)e^{i\omega t}\,d\omega$. The transform and its inverse form a pair, realizing the conversion between the time domain and the frequency domain.
Q3: How does the Fourier series differ from the Fourier transform?
A: The Fourier series expands a periodic function into discrete frequency components (integer multiples of the fundamental frequency). The Fourier transform also applies to non-periodic functions and handles a continuous frequency spectrum; it is obtained from the Fourier series in the limit of period $T \to \infty$.