Chapter 1: Definition and Arithmetic of Complex Numbers
Imaginary Unit, Four Operations, Conjugates, Absolute Value
Motivation
Within the real numbers, no number squares to a negative value. For example, the equation
$$x^2 + 1 = 0$$has no real solution, because $x^2 \geq 0$ for every real $x$, so $x^2 + 1 \geq 1 > 0$.
To resolve this, mathematicians introduced a new kind of number: the imaginary unit $i$.
Definition of the Imaginary Unit
Definition: Imaginary Unit
The imaginary unit $i$ is defined as a number satisfying:
$$i^2 = -1$$That is, $i = \sqrt{-1}$.
Powers of $i$
The powers of $i$ follow a cyclic pattern:
- $i^0 = 1$
- $i^1 = i$
- $i^2 = -1$
- $i^3 = i^2 \cdot i = -i$
- $i^4 = (i^2)^2 = (-1)^2 = 1$
- $i^5 = i^4 \cdot i = i$
- ...
The powers of $i$ repeat with period 4. In general, $i^n = i^{n \bmod 4}$.
Definition of Complex Numbers
Definition: Complex Number
A complex number is a number of the form:
$$z = a + bi$$where $a$ and $b$ are real numbers and $i$ is the imaginary unit.
- $a$ is called the real part of $z$, written $\mathrm{Re}(z) = a$
- $b$ is called the imaginary part of $z$, written $\mathrm{Im}(z) = b$
The set of all complex numbers is denoted $\mathbb{C}$.
Examples
- $z = 3 + 2i$: $\mathrm{Re}(z) = 3$, $\mathrm{Im}(z) = 2$
- $z = -1 + 4i$: $\mathrm{Re}(z) = -1$, $\mathrm{Im}(z) = 4$
- $z = 5$: $\mathrm{Re}(z) = 5$, $\mathrm{Im}(z) = 0$ (a real number is a special case of a complex number)
- $z = 3i$: $\mathrm{Re}(z) = 0$, $\mathrm{Im}(z) = 3$ (called a purely imaginary number)
Equality of Complex Numbers
Two complex numbers $z_1 = a_1 + b_1 i$ and $z_2 = a_2 + b_2 i$ are equal if and only if
$$a_1 = a_2 \quad \text{and} \quad b_1 = b_2$$That is, two complex numbers are equal precisely when their real parts and imaginary parts are respectively equal.
Arithmetic of Complex Numbers
Addition and Subtraction
For $z_1 = a_1 + b_1 i$ and $z_2 = a_2 + b_2 i$:
$$z_1 + z_2 = (a_1 + a_2) + (b_1 + b_2)i$$ $$z_1 - z_2 = (a_1 - a_2) + (b_1 - b_2)i$$In other words, add or subtract the real parts and imaginary parts separately.
Example: Addition and Subtraction
$(3 + 2i) + (1 - 4i) = (3+1) + (2-4)i = 4 - 2i$
$(3 + 2i) - (1 - 4i) = (3-1) + (2-(-4))i = 2 + 6i$
Multiplication
For $z_1 = a_1 + b_1 i$ and $z_2 = a_2 + b_2 i$:
\begin{align*} z_1 \cdot z_2 &= (a_1 + b_1 i)(a_2 + b_2 i) \\ &= a_1 a_2 + a_1 b_2 i + b_1 a_2 i + b_1 b_2 i^2 \\ &= a_1 a_2 + a_1 b_2 i + b_1 a_2 i - b_1 b_2 \quad (\because\; i^2 = -1) \\ &= (a_1 a_2 - b_1 b_2) + (a_1 b_2 + b_1 a_2)i \end{align*}Example: Multiplication
$(2 + 3i)(1 - i) = 2 \cdot 1 + 2 \cdot (-i) + 3i \cdot 1 + 3i \cdot (-i)$
$= 2 - 2i + 3i - 3i^2 = 2 + i + 3 = 5 + i$
Division
When $z_2 \neq 0$, $\displaystyle\frac{z_1}{z_2}$ is computed by multiplying by the conjugate of the denominator:
$$\frac{a_1 + b_1 i}{a_2 + b_2 i} = \frac{(a_1 + b_1 i)(a_2 - b_2 i)}{(a_2 + b_2 i)(a_2 - b_2 i)} = \frac{(a_1 a_2 + b_1 b_2) + (b_1 a_2 - a_1 b_2)i}{a_2^2 + b_2^2}$$Example: Division
Compute $\displaystyle\frac{3 + 2i}{1 - i}$. Multiply numerator and denominator by the conjugate $1 + i$:
$$\frac{3 + 2i}{1 - i} = \frac{(3 + 2i)(1 + i)}{(1 - i)(1 + i)} = \frac{3 + 3i + 2i + 2i^2}{1 - i^2} = \frac{3 + 5i - 2}{1 + 1} = \frac{1 + 5i}{2} = \frac{1}{2} + \frac{5}{2}i$$Complex Conjugate
Definition: Complex Conjugate
For a complex number $z = a + bi$, its complex conjugate $\bar{z}$ is defined as:
$$\bar{z} = a - bi$$That is, the sign of the imaginary part is reversed.
Properties of the Complex Conjugate
For complex numbers $z$ and $w$:
- $\overline{\bar{z}} = z$
- $\overline{z + w} = \bar{z} + \bar{w}$
- $\overline{z - w} = \bar{z} - \bar{w}$
- $\overline{z \cdot w} = \bar{z} \cdot \bar{w}$
- $\overline{\left(\frac{z}{w}\right)} = \frac{\bar{z}}{\bar{w}}$ ($w \neq 0$)
- $z + \bar{z} = 2\mathrm{Re}(z)$
- $z - \bar{z} = 2i\mathrm{Im}(z)$
- $z \cdot \bar{z} = |z|^2$ (see absolute value below)
Proof (selected)
Let $z = a + bi$ and $w = c + di$.
Proof of (2):
$$\overline{z + w} = \overline{(a+c) + (b+d)i} = (a+c) - (b+d)i = (a-bi) + (c-di) = \bar{z} + \bar{w}$$Proof of (6):
$$z + \bar{z} = (a + bi) + (a - bi) = 2a = 2\mathrm{Re}(z)$$Proof of (7):
$$z - \bar{z} = (a + bi) - (a - bi) = 2bi = 2i\mathrm{Im}(z)$$Absolute Value
Definition: Absolute Value of a Complex Number
The absolute value (or modulus) $|z|$ of a complex number $z = a + bi$ is defined as:
$$|z| = \sqrt{a^2 + b^2}$$This corresponds to the distance from the origin in the complex plane.
Relationship Between Absolute Value and Conjugate
For $z = a + bi$:
$$z \cdot \bar{z} = (a + bi)(a - bi) = a^2 - (bi)^2 = a^2 - b^2 i^2 = a^2 + b^2 = |z|^2$$Therefore, $|z| = \sqrt{z \cdot \bar{z}}$.
Properties of the Absolute Value
For complex numbers $z$ and $w$:
- $|z| \geq 0$, with equality if and only if $z = 0$
- $|\bar{z}| = |z|$
- $|zw| = |z||w|$
- $\displaystyle\left|\frac{z}{w}\right| = \frac{|z|}{|w|}$ ($w \neq 0$)
- $|z + w| \leq |z| + |w|$ (triangle inequality)
- $||z| - |w|| \leq |z - w|$
Proof (multiplicativity)
Let $z = a + bi$ and $w = c + di$.
$$|zw|^2 = (zw)\overline{(zw)} = zw \cdot \bar{z}\bar{w} = (z\bar{z})(w\bar{w}) = |z|^2|w|^2$$Since $|zw| \geq 0$ and $|z||w| \geq 0$, it follows that $|zw| = |z||w|$.
Examples: Computing Absolute Values
- $|3 + 4i| = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5$
- $|1 - i| = \sqrt{1^2 + (-1)^2} = \sqrt{2}$
- $|5| = \sqrt{5^2 + 0^2} = 5$ (agrees with the real absolute value)
- $|3i| = \sqrt{0^2 + 3^2} = 3$
Multiplicative Inverse
Inverse of a Complex Number
For $z \neq 0$, the multiplicative inverse $z^{-1} = \displaystyle\frac{1}{z}$ is given by:
$$\frac{1}{z} = \frac{\bar{z}}{|z|^2}$$Derivation
$$\frac{1}{z} = \frac{1}{z} \cdot \frac{\bar{z}}{\bar{z}} = \frac{\bar{z}}{z\bar{z}} = \frac{\bar{z}}{|z|^2}$$Example: Computing an Inverse
Find the inverse of $z = 3 + 4i$.
$|z|^2 = 3^2 + 4^2 = 25$, $\bar{z} = 3 - 4i$, so
$$\frac{1}{3 + 4i} = \frac{3 - 4i}{25} = \frac{3}{25} - \frac{4}{25}i$$Summary
- The imaginary unit $i$ satisfies $i^2 = -1$
- A complex number $z = a + bi$ consists of a real part $a$ and an imaginary part $b$
- Arithmetic uses the rule $i^2 = -1$
- The complex conjugate $\bar{z} = a - bi$ reverses the sign of the imaginary part
- The absolute value $|z| = \sqrt{a^2 + b^2}$ is the distance from the origin
- $z\bar{z} = |z|^2$